A carpenter has to cut a rectangular beam from a circular log. The strongest rectangular beam is the one whose length is 2.3 times the radius of the log. What is the length of the strongest beam that can be cut from a log 12 inches in diameter? (JUSTIFY)

A carpenter has to cut a rectangular beam from a circular log The strongest rectangular beam is the one whose length is 23 times the radius of the log What is t class=

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Answer:

The length of the strongest beam is 13.8 inches

Step-by-step explanation:

* Lets explain how to solve this problem

- There is circular log with radius r

- There is a rectangular beam of length l is cutting from the circular log

- The strongest rectangular beam is the one whose length is 2.3 times

 the radius of the log

∴ l = 2.3 r

- The diameter of the circular beam is 12 inches

- Use the formula above to find the length of the strongest beam

∵ The diameter of the circular log is 12 inches

∵ the radius of the circle = half the diameter of the circle

∴ r = 1/2 × the diameter

∴ r = 1/2 × 12 = 6 inches

∵ l = 2.3 r

∴ l = 2.3 × 6 = 13.8 inches

* The length of the strongest beam is 13.8 inches

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