Question

I NEED help Please

f(a)= -1/4(a+8)

g(b)=2/3b+1

g(f(6))


need help with this composite function

Answer 1

Answer:

$\large\boxed{g\bigg(f(6)\bigg)=-\dfrac{4}{3}}$

Step-by-step explanation:

$f(a)=-\dfrac{1}{4}(a+8)\\\\g(b)=\dfrac{2}{3}b+1\\\\g\bigg(f(6)\bigg)\\\\\text{calculate}\ f(6)\to\text{put}\ a=6\ \text{to the equation of}\ f(a):\\\\f(6)=-\dfrac{1}{4}(6+8)=-\dfrac{1}{4}(14)=-\dfrac{14}{4}=-\dfrac{7}{2}\\\\g\bigg(f(6)\bigg)\to\text{put}\ b=-\dfrac{7}{2}\ \text{to the equation of}\ g(b):\\\\g\bigg(f(6)\bigg)=\dfrac{2}{3}\left(-\dfrac{7}{2}\right)+1=-\dfrac{7}{3}+1=-\dfrac{7}{3}+\dfrac{3}{3}=-\dfrac{4}{3}$