Answer:
Step-by-step explanation:
The point-slope form of an equationo f a line:
[tex]y-y_1=m(x-x_1)[/tex]
m - slope
We have
[tex]y+2=-2(x-5)\\\\y-(-2)=-2(x-5)[/tex]
Therefore we have
the slope: m = -2
the point: (5, -2) not (-5, 2)!!!
The slope-intercept form of an equation of a line:
[tex]y=mx+b[/tex]
m - slope
b - y-intercept
Convert:
[tex]y+2=-2(x-5)[/tex] use the distributive property a(b + c) = ab + ac
[tex]y+2=-2x+10[/tex] subtract 2 from both sides
[tex]y=-2x+8[/tex]