Answer:
(3, 2)
Step-by-step explanation:
First, we have to eliminate a variable:
3(5x+2y = 19 )
2(4x-3y = 6)
------------------
15x+6y = 57
8x-6y = 12
Now we add the system of equations together:
15x+8x+6y-6y = 57+12
23x = 69
/23 /23
x = 3
Now we can plug this value back into one of the equations to get y:
5(3)+2y = 19
15+2y = 19
-15 -15
2y = 4
/2 /2
y = 2
Therefore, the solution to these system of equations is (3, 2)
Answer:
The solution of given system of equation is (3,2).
Step-by-step explanation:
The given system of equations is
[tex]5x+2y=19[/tex] .... (1)
[tex]4x-3y=6[/tex] .... (2)
Solve the system of equations using elimination method.
Multiply equation (1) by 3 and multiply equation (2) by 2.
[tex]15x+6y=57[/tex] .... (3)
[tex]8x-6y=12[/tex] .... (4)
Now, add the equations (3) and (4), to eliminate y.
[tex]15x+8x=57+12[/tex]
[tex]23x=69[/tex]
Divide both sides by 23.
[tex]x=3[/tex]
The value of x is 3. Substitute x=3 in equation (1), to find the value of y.
[tex]5(3)+2y=19[/tex]
[tex]15+2y=19[/tex]
Subtract 15 from both the sides.
[tex]2y=19-15[/tex]
[tex]2y=4[/tex]
Divide both sides by 2.
[tex]y=2[/tex]
The value of y is 2.
Therefore the solution of given system of equation is (3,2).
