Question

Julie is walking around a track at a 2m/s for some exercise. She then decides to start jogging so she accelerates at a rate of 0.5m/s² for 3 seconds. How far did Julie travel from the time she started to accelerate to the end of the 3 seconds?

Answer 1

Answer:

The distance is 8.25 m.

Explanation:

Given  that,

Speed = 2 m/s

Acceleration = 0.5 m/s^2

Time = 3 sec

We need to calculate the distance

Using equation of motion

$s = ut+\dfrac{1}{2}at^2$

Where, u = initial velocity

a = acceleration

t = time

Put the value in the equation

$s=2\times3+\dfrac{1}{2}\times0.5\times3^2$

$s=8.25\ m$

Hence, The distance is 8.25 m.

Answer 2

Julie's distance at the end of the 3 seconds is 8.25 m.

To calculate the distance traveled by Julie at the end ]of 3 seconds, we use the formula below.

Formula:

• s = ut+at²/2.............. Equation 1

Where:

• s = distance traveled by Julie after 3 seconds
• u = Initial velocity
• t = time
• a = acceleration.

From the question,

Given:

• u = 2 m/s
• a = 0.5 m/s²
• t = 3 seconds

Substitute these given values into equation 1

• s = 2(3)+(0.5×3²)/2
• s = 6+2.25
• s = 8.25 m

Hence, Julie's distance at the end of the 3 seconds is 8.25 m.
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