Answer with explanation:
The Inequality should be:
[tex](1+x)^n\geq 1+n x[/tex]
Where, n and x are any integers.
⇒For, x= -1
L HS
[tex]=[1+(-1)]^n\\\\=(0)^n\\\\=0[/tex]
R HS
→1+n × (-1)
=1-n
If, n is any Integer, then for, n=1
1-1=0
For, n=2
1-2= -1
....
So, [tex](1+x)^n\geq 1+n x[/tex]
for, x=-1.
⇒For, x=1
L HS
[tex]=[1+(1)]^n\\\\=(2)^n[/tex]
For, n=1
L H S=1
For, =2
L H S=4
R HS
→1+n × (1)
=1+n
If, n is any Integer, then for, n=1
1+1=2
For, n=2
1+2= 3
....
So, [tex](1+x)^n\geq 1+n x[/tex]
for, x=1.