Respuesta :

Answer with explanation:

The Inequality should be:

   [tex](1+x)^n\geq 1+n x[/tex]

Where, n and x are any integers.

For, x= -1

L HS

 [tex]=[1+(-1)]^n\\\\=(0)^n\\\\=0[/tex]

R HS

→1+n × (-1)

=1-n

If, n is any Integer, then for, n=1

1-1=0

For, n=2

1-2= -1

....

So,   [tex](1+x)^n\geq 1+n x[/tex]

for, x=-1.

⇒For, x=1

L HS

 [tex]=[1+(1)]^n\\\\=(2)^n[/tex]

For, n=1

L H S=1

For, =2

L H S=4

R HS

→1+n × (1)

=1+n

If, n is any Integer, then for, n=1

1+1=2

For, n=2

1+2= 3

....

So,    [tex](1+x)^n\geq 1+n x[/tex]

for, x=1.

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