Explanation:
It is given that,
Frequency of diagnostic ultrasound, f = 3.82 MHz = 3820 Hz
The speed of the sound in air, v = 343 m/s
(a) We need to find the wavelength in air of such a sound wave. Let it is given by λ₁
i.e. [tex]\lambda=\dfrac{v}{\nu}[/tex]
[tex]\lambda_1=\dfrac{343\ m/s}{3820\ Hz}[/tex]
[tex]\lambda_1=0.089\ m[/tex]
(b) If the speed of sound in tissue is 1650 m/s .
[tex]\lambda_2=\dfrac{v}{\nu}[/tex]
[tex]\lambda_2=\dfrac{1650\ m/s}{3820\ Hz}[/tex]
[tex]\lambda_2=0.43\ m[/tex]
Hence, this is the required solution.