Question

A 1.7cm diameter pipe widens to 4.7cm. Liquid flows through the first segment at a speed of 4.7m/s. What is the speed of the liquid in the second segment?

Answer 1

Answer:

Speed of the liquid in the second segment = 0.61 m/s

Explanation:

This discharge is constant.

That is

        Q₁ = Q₂

       A₁v₁ = A₂v₂

       $\frac{\pi d_1^2}{4}\times v_1=\frac{\pi d_2^2}{4}\times v_2\\\\\frac{\pi \times 1.7^2}{4}\times 4.7=\frac{\pi \times 4.7^2}{4}\times v_2\\\\v_2=0.61m/s$

Speed of the liquid in the second segment = 0.61 m/s