Answer:
Electrical energy consumed, E = 1.95 × 10⁻⁵ kWh
Explanation:
It is given that,
Power rating on the light bulb, P = 75 W
We need to find the electrical energy consumed by the bulb in 1 second of time i.e in 0.00026 hours.
[tex]P=\dfrac{energy\ consumed}{time}[/tex]
Energy consumed, E = P × t
E = 75 W × 0.00026 h
E = 0.0195 W-h
Energy consumed is calculated in kilo watt hour. Since, 1 watt = 0.001 kW
So, E = 1.95 × 10⁻⁵ kWh
Hence, this is the required solution.
