Quadratic formula:
[tex]$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$[/tex]
Input the corresponding numbers:
[tex]$x=\frac{-12\pm\sqrt{12^2-4(1)(32)}}{2(1)}$[/tex]
Solve:
[tex]x=\frac{-12+\sqrt{12^2-4(1)(32)}}{2(1)}\\ x = -4\\ \\ x=\frac{-12-\sqrt{12^2-4(1)(32)}}{2(1)}\\ x=-8[/tex]
So, the solutions are x = -4 and x = -8
