Hence, the probability is:
0.8846
D be the event that the card drawn is red.
and F denote the event that the card drawn is a face card.
We are asked to find:
P(D'∪F')
We know that D' denote the complement of event D
and F' denote the complement of event F.
Hence, we have:
[tex]P(D'\bigcup F')=(P(D\bigcap F))'\\\\i.e.\\\\P(D'\bigcup F')=1-P(D\bigcap F)[/tex]
D∩F denote the event that the card is a red card and is a face card as well
Since there are 6 cards which are face as well as red cards out of a total of 52 cards.
Hence, we get:
[tex]P(D'\bigcup F')=1-\dfrac{6}{52}\\\\i.e.\\\\P(D'\bigcup F')=\dfrac{52-6}{52}\\\\i.e.\\\\P(D'\bigcup F')=\dfrac{46}{52}\\\\P(D'\bigcup F')=0.8846[/tex]