Respuesta :
Answer:
B
Explanation:
Use conservation of momentum: Total momentum of the system before is the same as the total momentum after the collision. Since both are moving north, the momentum of both cars is in the same direction, and the total momentum before collision is 1000kg*20m/s + 1500kg*36m/s = 74000kg-m/s.
This is the same amount of momentum after collision, and since they are locked together, their mass is added. The velocity can be found by: 74000kg-m/s ÷ 2500kg = 29.6m/s.
momentum = mass*velocity
The velocity after collision is 29.6 m/s due north.
To find the correct option among all the options, we need to know about the the velocity expression just after an inelastic collision.
What is the velocity expression just after an inelastic collision?
- In an inelastic collision, the linear momentum is conserved.
- Let m1 and m2 are the masses of two objects and u1 and u2 are their velocities before the collision respectively.
- Total linear momentum before collision is (m1×u1) + (m2×u2).
- If v is the velocity just after the collision, momentum after collision is (m1+m2)×v.
- From conservation of momentum, (m1×u1) + (m2×u2) = (m1+m2)×v
v = ((m1×u1) + (m2×u2))/(m1+M2)
What will be the final velocity in an inelastic collision, if m1 = 1000 Kg, M2 = 1500Kg, u1= 20m/s and u2 = 36 m/s?
So, v = {(1000×20)+(1500×36)}/(1000+1500)
=74000/2500
=29.6 m/s
Thus, we can conclude that the velocity just after the collision is 29.6m/s.
Learn more about the inelastic collision here:
rainly.com/question/15742157
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