Answer:
Total momentum of the system is 378 kg-m/s
Explanation:
It is given that,
Mass of first bumper car, m₁ = 222 kg
Velocity of first bumper car, v₁ = 3.10 m/s (in right)
Mass of other bumper car, m₂ = 165 kg
Velocity of second bumper car, v₂ = -1.88 m/s (in left)
Momentum of the system is given by the product of its mass and velocity. So, the total momentum of this system is given by :
[tex]p=m_1v_1+m_2v_2[/tex]
[tex]p=222\ kg\times 3.10\ m/s+165\ kg\times (-1.88\ m/s)[/tex]
p = 378 kg-m/s
Hence, the total momentum of the system is 378 kg-m/s
