Answer:
For 1: 3.3 moles of oxygen gas is required.
For 2: 14 moles of hydrogen gas is required.
For 3: 1.5 moles of oxygen gas is required.
Explanation:
The chemical reaction of oxygen and hydrogen to form water follows:
[tex]O_2+2H_2\rightarrow 2H_2O[/tex]
By Stoichiometry of the above reaction:
2 moles of hydrogen gas reacts with 1 mole of oxygen gas.
So, 6.6 moles of hydrogen gas will react with = [tex]\frac{1}{2}\times 6.6=3.3mol[/tex] of oxygen gas.
Hence, 3.3 moles of oxygen gas is required.
By Stoichiometry of the above reaction:
1 mole of oxygen gas reacts with 2 moles of hydrogen gas.
So, 7 moles of oxygen gas will react with = [tex]\frac{2}{1}\times 7=14mol[/tex] of hydrogen gas.
Hence, 14 moles of hydrogen gas is required.
By Stoichiometry of the above reaction:
2 moles of water is formed from 1 mole of oxygen gas.
So, 3.0 moles of water will be formed from = [tex]\frac{1}{2}\times 3.0=1.5mol[/tex] of oxygen gas.
Hence, 1.5 moles of oxygen gas is required.