Respuesta :
Answer: The mass of water that can be formed are 33.48 g.
Explanation:
To calculate the number of moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex] ....(1)
- For ammonia gas:
Given mass of ammonia gas = 21.1 g
Molar mass of ammonia gas = 17 g/mol
Putting values in above equation, we get:
[tex]\text{Moles of ammonia}=\frac{21.1g}{17g/mol}=1.24mol[/tex]
- For oxygen gas:
Given mass of oxygen gas = 73.9 g
Molar mass of oxygen gas = 32 g/mol
Putting values in above equation, we get:
[tex]\text{Moles of oxygen gas}=\frac{73.9g}{32g/mol}=2.30mol[/tex]
For the given chemical equation:
[tex]4NH_3(g)+5O_2(g)\rightarrow 4NO(g)+6H_2O(l)[/tex]
By Stoichiometry of the reaction:
4 moles of ammonia gas reacts with 5 moles of oxygen gas.
So, 1.24 moles of ammonia gas will react with = [tex]\frac{5}{4}\times 1.24=1.55moles[/tex] of oxygen gas.
As, given amount of oxygen gas is more than the required amount. Thus, it is considered as an excess reagent.
So, ammonia gas is considered as a limiting reagent because it limits the formation of products.
By Stoichiometry of the above reaction:
4 moles of ammonia gas is producing 6 moles of water.
So, 1.24 moles of ammonia gas will produce = [tex]\frac{6}{4}\times 1.24=1.86moles[/tex] of water.
Now, calculating the mass of water by using equation 1, we get:
Moles of water = 1.86 moles
Molar mass of water = 18 g/mol
Putting all the values in equation 1, we get:
[tex]1.86mol=\frac{\text{Mass of water}}{18g/mol}\\\\\text{Mass of water}=33.48g[/tex]
Hence, the mass of water that can be formed are 33.48 g
