Question

Which shows how to find the value of this expression when X=-2 and Y = 5?
(3x3y=272
31-216
(-2)4
21954

Answer 1

Answer:

Option 1 is correct

Step-by-step explanation:

Given expression is:

$(3x^3y^{-2})^2$

Putting the values

$= [3 (-2)^3 (5)^{-2}]^2\\We\ have\ to\ make\ the\ powers\ positive\\= [{\frac{3(-2)^3}{5^{2}} }]^2\\= \frac{[{3(-2)^3}]^2}{(5^2)^2} \\Applying\ outer\ power\\= \frac{3^2(-2)^6}{5^4}$

Hence option one is correct ..

Answer 2

Answer:

he's right it's A because i just took the test and i got it right

Step-by-step explanation: