Question

solve the equations. log(2x-3)=log(3-x)-2
$log(2x - 3) = log(3 - x) - 2$
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Answer 1

Answer:

1.59

Step-by-step explanation:

log (2x-3)= log (3-x) -2

log (2x-3)/(3-x) =-2

If we remove log,

2x-3/(3-x) = e^-2

2x-3= 3e^-2 -xe^-2

2x+ xe^-2 = 3e^-2+3

x(2+e^-2) = 3( e^-2+1)

If you use calculator you will get answer nearly equal to 1.59.