Respuesta :

Answer:

This solution is neutral.

Assumption: the solution is under room temperature, such that [tex]K_w = 10^{-14}[/tex].

Explanation:

For a solution in water,

[tex]\mathrm{[H_3O^{+}] \cdot [OH^{-}]} = \mathnormal{K_w}[/tex].

In other words, if [tex]K_w[/tex] is given, knowing the concentration (in [tex]\rm M[/tex], or equivalently [tex]\rm mol\cdot L^{-1}[/tex]) of either [tex]\rm H_3O^{+}[/tex] or [tex]\rm OH^{-}[/tex] will imply the concentration of the other ion.

Under room temperature,

[tex]K_w \approx 10^{-14}[/tex].

The question states that for this solution,

[tex]\mathrm{[H_3O^{+}]} = \rm 1.00\times 10^{-7}\; M[/tex]

As a result, the concentration of [tex]\rm OH^{-}[/tex] in this solution will be

[tex]\displaystyle \frac{K_w}{\mathrm{[H_3O^{+}]}} = \frac{10^{-14}}{1.00\times 10^{-7}} = 10^{-7}[/tex].

  • A solution is acidic if [tex]\mathrm{[H_3O^{+}] > [OH^{-}]}[/tex].
  • A solution is basic if [tex]\mathrm{[H_3O^{+}] < [OH^{-}]}[/tex].
  • A solution is neutral if [tex]\mathrm{[H_3O^{+}] = [OH^{-}]}[/tex].

In this case, [tex]\rm [H_3O^{+}] = 10^{-7}\; M = [OH^{-}][/tex]. In other words, this solution is neutral.

ACCESS MORE