Answer:
4.33g
Explanation:
The reaction equation is given as:
2HgO → 2Hg + O₂
Given parameters:
Mass of HgO = 58.67g
Mass of Hg produced = 54.34g
Unknown:
Mass of oxygen produced = ?
Solution
From the reaction equation, using the mole concept, it is possible to determine the mass of oxygen gas produced.
To do this, we first determine the molar composition of the mass of the given mercury oxide. Then we use the balanced reaction equation to determine the mass of oxygen produced:
Number of moles of HgO = [tex]\frac{mass of HgO}{Molar mass of HgO}[/tex]
Molar mass of HgO = 200.6 + 16 = 216.6gmol⁻¹
Number of moles of HgO = [tex]\frac{58.67}{216.6}[/tex] = 0.271mol
From the reaction equation, we know that:
2moles of HgO produced 1 mole of O₂
0.271moles of HgO would also produce, 0.136mol
Therefore, mass of O₂ gas produced = number of moles of O₂ x molar mass
Molar mass of O₂ = 16x2 = 32gmol⁻¹
Mass of O₂ gas = 0.136 x 32 = 4.33g
