Answer:
Acceleration due to gravity value
[tex]=9.89m/ {s}^{2} [/tex]
Explanation:
Time period of simple pendulum is given by the expression
[tex]T=2\pi\sqrt{\frac{l}{g}} \\ [/tex]
Here we have
T = 0.88 s
l = 19.4 cm = 0.194 m
Substituting
[tex]0.88=2\pi\sqrt{\frac{0.194}{g}}\\\\\frac{0.194}{g}=0.0196\\\\g=9.89m/s^2 \\ [/tex]
Acceleration due to gravity value
[tex]=9.89m/s^2 \\ [/tex]
