Question

What is the escape speed (in km/s) from an Earth-like planet with mass 6.5e+24 kg and radius 55.0 × 105 m? Use the gravitational constant G = 6.67 × 10-11 m3 kg-1 s-2.

Answer 1

Answer:

Escape velocity, v = 12.6 km/s

Explanation:

It is given that,

Mass of earth like planet, $m=6.5\times 10^{24}\ kg$

Radius of planet, $r=55\times 10^5\ m$

The escape velocity of a planet is given by the following formula as:

$v=\sqrt{\dfrac{2Gm}{r}}$

G = universal gravitational constant

$v=\sqrt{\dfrac{2\times 6.67\times 10^{-11}\ m^3kg^{-1}s^{-2}\times 6.5\times 10^{24}\ kg}{55\times 10^5\ m}$

v = 12556.05 m/s

or

v = 12.6 km/s

Hence, this is the required solution.