Question

What is the emf through a single coil of wire if the magnetic flux changes from -57 Wb to +43 Wb in 0.17 s? O 588 V O 344 V O 386 V O 496 V

Answer 1

Answer:

Emf through a single coil of wire is 588 V.

Explanation:

We need to find the emf through a single coil of wire if the magnetic flux changes from -57 Wb to +43 Wb in 0.17 s

According to Faraday's law, emf of coil is directly proportional to the rate of change of magnetic flux. It can be written as :

$\epsilon=\dfrac{d\phi}{dt}$

Initial flux, $\phi_1=-57\ Wb$

Final flux, $\phi_2=+43\ Wb$

So, $\epsilon=\dfrac{\phi_2-\phi_1}{dt}$

$\epsilon=\dfrac{43\ Wb-(-57\ Wb)}{0.17\ s}$

$\epsilon=588.23\ V$

or

$\epsilon=588\ V$

So, the EMF through a single coil of wire is 588 V. Hence, this is the required solution.