Question

The maximum force measured on a 3.72 m wire is 0.731 N when the magnetic field is 0.093 T. What current flows through the wire? O 2.36 A O 225A O 2.11 A O 218

Answer 1

Answer:

Current, I = 2.11 A

Explanation:

It is given that,

Length of the wire, L = 3.72 m

Maximum force on the wire, F = 0.731 N

Magnetic field, B = 0.093 T

We have to find the current flowing the wire. The force acting on the wire is given by :

$F=lLB\ sin\theta$

When $\theta=90$, F = maximum

So, $F=ILB$

$I=\dfrac{F}{LB}$

$I=\dfrac{0.731\ N}{3.72\ m\times 0.093\ T}$

I = 2.11 A

So, the current flowing through the wire is 2.11 A. Hence, the correct option is (c).