Question

What current is produced if 1473 sodium ions flow across a cell membrane every 3.4ju8? 0 5.81 pA O 694 pA O 7.76 pA 5.99 pA

Answer 1

Answer:

69.4 pA

Explanation:

n = number of sodium ions = 1473

e = magnitude of charge on each sodium ion = 1.6 x 10⁻¹⁹ C

t = time taken to flow across the membrane = 3.4 x 10⁻⁶ sec

Total Charge on sodium ions is given as

q = n e                                            eq-1

Current produced is given as

$i = \frac{q}{t}$

Using eq-1

$i = \frac{ne}{t}$

Inserting the values

$i = \frac{(1473)(1.6\times 10^{-19})}{3.4\times 10^{-6}}$

i = 69.4 x 10⁻¹² A

i = 69.4 pA