Question

5 hatfields and five McCoys are up for 3 jobs. What is the probability that all 3 jobs go to the hatfields?

Answer 1

Answer:

$P =\frac{1}{12}$

Step-by-step explanation:

The probability is defined as the number of ways to obtain the desired result among the number of possible outcomes.

The number of possible ways to select 3 hatfields from a group of 5 hatfields is:

$3C5 =\frac{5!}{3!(5-3)!} =10$

The number of ways to select 3 people from a group of 10 is:

$10C3 =\frac{10!}{3!(10-3)!} =120$

Then the probability is:

$P =\frac{10}{120}$

$P =\frac{1}{12}$