[tex]\bf \cfrac{x}{2}+\cfrac{y}{3}-\cfrac{z}{4}\implies \stackrel{\textit{using the LCD of 12}}{\cfrac{(6)x~~+~~(4)y~~-~~(3)z}{12}}\implies \cfrac{6x+4y-3z}{12}[/tex]
Question: Perform the indicated operation. [tex]\frac{x}{2}+\frac{y}{3}-\frac{z}{4} = ?[/tex]
Answer: [tex]\frac{6x+4y-3z}{12}[/tex]
Hope I helped!!! :)
(I had this same question)
