Answer:
Option B is correct.
Step-by-step explanation:
[tex]2(\frac{3}{5}x+ 2\frac{3}{4}y-\frac{1}{4}x-1\frac{1}{2}y+3)[/tex]
We need to solve the above expression.
First Convert Mix fraction into improper fraction
[tex]2(\frac{3}{5}x+ 2\frac{3}{4}y-\frac{1}{4}x-1\frac{1}{2}y+3)\\=2(\frac{3}{5}x+ \frac{11}{4}y-\frac{1}{4}x-\frac{3}{2}y+3)[/tex]
Combining the like terms
[tex]=2(\frac{3}{5}x-\frac{1}{4}x+ \frac{11}{4}y-\frac{3}{2}y+3)[/tex]
Solving like terms
[tex]=2(\frac{3x*4-5x}{20}+ \frac{11y-3y*2}{4}+3)\\=2(\frac{12x-5x}{20}+ \frac{11y-6y}{4}+3)\\=2(\frac{7x}{20}+ \frac{5y}{4}+3)[/tex]
Multiply each term with 2
[tex]=2*\frac{7x}{20}+ 2*\frac{5y}{4}+2*3\\=\frac{7x}{10}+ \frac{5y}{2}+6[/tex]
[tex]=\frac{7x}{10}+ 2\frac{1}{2}y+6[/tex]
So, Option B is correct.
