The expression log1/3/log2 is the result of applying the change of base formula to a logarithmic expression. Which could be the original expression? ​

The expression log13log2 is the result of applying the change of base formula to a logarithmic expression Which could be the original expression class=

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Answer:

Option C. [tex]log_{2}\frac{1}{3}[/tex]

Step-by-step explanation:

The given logarithmic expression is [tex]\frac{log(\frac{1}{3} )}{log2}[/tex]

Rule of logarithm says

[tex]\frac{log_{e}a }{log_{e}b}=log_{b}a[/tex]

So by this rule,

expression [tex]\frac{log(\frac{1}{3} )}{log2}[/tex] will become [tex]log_{2}\frac{1}{3}[/tex]

Therefore, Option C. [tex]log_{2}\frac{1}{3}[/tex] will be the answer.

To solve the problem we must know about the rule to change the base of any logarithmic expression.

The solution of the given expression  [tex]\dfrac{log\dfrac{1}{3}}{log 2}[/tex]  is  [tex]\rm log_2\dfrac{1}{3}[/tex].

What is the rule for changing the base of a logarithm expression?

The formula which helps us to change the base of any logarithm expression,

[tex]\rm log_ab = \dfrac{log_cb}{log_ca}[/tex]

Given to us

[tex]\dfrac{log\dfrac{1}{3}}{log 2}[/tex]

As we have already discussed the formula for the change of the base of any logarithm expression, comparing the formula with that expression,

[tex]\rm log_ab = \dfrac{log_cb}{log_ca} = \dfrac{log\dfrac{1}{3}}{log 2}[/tex]

[tex]\rm log_2\dfrac{1}{3} = \dfrac{log\dfrac{1}{3}}{log 2}[/tex]

Hence, the solution of the given expression  [tex]\dfrac{log\dfrac{1}{3}}{log 2}[/tex]  is  [tex]\rm log_2\dfrac{1}{3}[/tex].

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