For this case we must factor the following expression:
[tex]x ^ 3-y ^ 3[/tex]
We have that since both terms are perfect cubes, we factor using the cube difference formula.
[tex]a ^ 3-b ^ 3 = (a-b) (a ^ 2 + ab + b ^ 2)[/tex]
Where:
[tex]a = x\\b = y[/tex]
So, we have to:
[tex]x ^ 3-y ^ 3 = (x-y) (x ^ 2 + xy + y ^ 2)[/tex]
Answer:
[tex]x ^ 3-y ^ 3 = (x-y) (x ^ 2 + xy + y ^ 2)[/tex]