Answer:
No
Step-by-step explanation:
g(x)= 5x-1 is the same as g(x)= 5x^1 - 1x^0, which contains one odd power (x^1) and one even power (x^0). Therefore, g(x)= 5x-1 is neither even nor odd.
Answer:
Step-by-step explanation:
[tex]\text{If}\ f(-x)=f(x)\ \text{then}\ f(x)\ \text{is an even function.}\\\\\text{If}\ f(-x)=-f(x)\ \text{then}\ f(x)\ \text{is an odd function.}[/tex]
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[tex]g(x)=5x-1\\\\g(-x)=5(-x)-1=-5x-1=-(5x+1)\\\\g(-x)\neq-g(x)\ \wedge\ g(-x)\neq g(x)[/tex]