Question

PLEASE HELP AS FAST AS POSSIBLE PLEASE
Find the product of (-8y2 + 3) and (-4y - 3).

A) 32y3 + 24y2 - 12y - 9

B) -32y3 - 24y2 + 12y - 9

C) 12y3 - 12y - 9

D) -8y2 - 4y - 9

Answer 1

Answer:

A) 32y³ + 24y² - 12y - 9

Step-by-step explanation:

(-8y² + 3)(-4y - 3) = (-8y² x -4y) + (-8y² x -3) + (3 x -4y) + (3 x -3)

                           = 32y³ + 24y² - 12y - 9

Answer 2

Answer:

The product of $-8y^2+3$ and $-4y-3$ is:

               $32y^3+24y^2-12y-9$

Step-by-step explanation:

We are asked to find the product of the two expressions which are given by:

$-8y^2+3$ and $-4y-3$

i.e.

we are asked to find the product of a quadratic and a linear polynomial.

We are asked to find the result of:

$(-8y^2+3)\cdot (-4y-3)$

Hence, on using the distributive property we have:

$-8y^2(-4y-3)+3(-4y-3)\\\\=-8y^2\times -4y-8y^2\times (-3)+3\times (-4y)+3\times (-3)\\\\i.e.\\\\=32y^3+24y^2-12y-9$

The correct answer is: Option: A