Answer:
[tex]\large\boxed{D.\ 2160\pi\ units^3}[/tex]
Step-by-step explanation:
[tex]\text{The formula of a volume of a cylinder:}\\\\V=\pi r^2H\\\\r-radius\\\H-height\\\\\text{We have}\ r=12\ \text{and}\ H=15.\ \text{Substitute:}\\\\V=\pi(12^2)(15)=\pi(144)(15)=2160\pi[/tex]
