Question

Consider the reaction. CaCl2(aq)+K2CO3(aq)⟶CaCO3+2KCl. Identify the precipitate, or lack thereof, for the reaction. (A) KCl (B) CaCO3 (C) no precipitate

Answer 1

Answer: The correct answer is Option B.

Explanation:

Precipitate is defined as insoluble solid substance that emerges when two different aqueous solutions are mixed together. It usually settles down at the bottom of the solution after sometime.

For the given chemical equation:

$CaCl_2(aq.)+K_2CO_3(aq.)\rightarrow CaCO_3(s)+2KCl(aq.)$

The products formed in the reaction are calcium carbonate and potassium chloride. Out of the two products, one of them is insoluble which is calcium carbonate. Thus, it is considered as a precipitate.

Hence, the correct answer is Option B.

Answer 2

In the double displacement reaction between CaCl₂ and K₂CO₃, CaCO₃ is the precipitate (B).

Let's consider the following double displacement reaction.

CaCl₂(aq) + K₂CO₃(aq) ⟶ CaCO₃(s) + 2 KCl(aq)

Regarding solubility rules, we know that:

• Carbonates are often insoluble (except Group 1 carbonates).
• Chlorides are often soluble (except AgCl, PbCl₂ and Hg₂Cl₂).
• Salts with cations from Group 1 are often soluble.

With this information, we can conclude that CaCO₃ is a precipitate.

In the double displacement reaction between CaCl₂ and K₂CO₃, CaCO₃ is the precipitate (B).

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