The probability that the team will win exactly 7 matches over the course of one season is:
0.1977
We know that the probability of k successes out of n successes is given by the binomial distribution as:
[tex]P(X=k)=n_C_kp^k(1-p)^{n-k}[/tex]
where p is the probability of success .
Here we are asked to find the probability that the team will win exactly 7 matches over the course of one season.
Since, there are 8 matches over the course of season.
This means n=8
and k=7
and p=0.70
(Since, 0.70 probability of winning a match )
Hence, we get:
[tex]P(X=7)=8_C_7\times (0.70)^7\times (1-0.70)^{8-7}\\\\i.e.\\\\P(X=7)=8\times (0.70)^7\times 0.30\\\\i.e.\\\\P(X=7)=0.1977[/tex]
Hence, the answer is:
0.1977