Question

Figure ABCD is a parallelogram.
What are the lengths of line segments AB and BC?
A
3y - 2
B
AB = 4; BC = 16
OAB = 4; BC = 8
AB = 10; BC = 20
OAB = 10; BC = 28
2x - 4
x + 12
y + 6

Answer 1

First you need know that AB = DC and AD = BC.

So,

3y - 2 = y + 6

2y = 8

y = 4

AB = 3(4) - 2 = 12 - 2 = 10

2x - 4 = x + 12

x = 12 + 4

x = 16

BC = 16 + 12 = 28

So your answer is:

AB = 10; BC = 28

Answer 2

The lengths of line segments AB = 10 and BC = 28.

How to estimate the lengths of line segments?

The opposite sides of a parallelogram are congruent,

AB = DC,

3y - 2 = y + 6

subtract y from both sides, then we get

2y - 2 = 6

adding 2 to both sides

2y = 8

Dividing both sides by 2, then we get

y = 4

Hence AB = 3y - 2 = (3 × 4) - 2 = 12 - 2 = 10

and AD = BC, that exists

2x - 4 = x + 12

subtract x from both sides

x - 4 = 12

adding 4 to both sides

x = 16

BC = x + 12 = 16 + 12 = 28

The lengths of line segments AB = 10 and BC = 28.

Therefore, the correct answer is AB = 10 and BC = 28.

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