Answer: 14
Step-by-step explanation:
f(x) = 3x + 2
To find f⁻¹, swap the x's and y's and solve for y --> Note: f(x) is y
x = 3y + 2
x - 2 = 3y
[tex]\dfrac{x-2}{3}=y[/tex]
[tex]\implies f^{-1}(x)=\dfrac{x-2}{3}[/tex]
[tex]\implies f^{-1}(14)=\dfrac{14-2}{3}[/tex]
[tex]\implies f^{-1}(14)=\dfrac{12}{3}[/tex]
[tex]\implies f^{-1}(14)=4[/tex]
f(f⁻¹(14)) = f(4)
f(4) = 3(4) + 2
= 12 + 2
= 14
NOTE: the simplified version is .... f and f⁻¹ cancel out, leaving you with 14