Question

Almost doneeeeeeeeeeeeeeee

Answer 1

We know that According to Algebra of Real Functions :  

If f and g are two real functions which are defined under the same domain then (f + g)(x) = f(x) + g(x)

Given : f(x) = 2x - 1 and g(x) = x² - 3x - 2

$:\implies$ (f + g)(x) = f(x) + g(x) = (2x - 1) + (x² - 3x - 2)

$:\implies$  (f + g)(x) = f(x) + g(x) = x² - 3x + 2x - 1 - 2

$:\implies$  (f + g)(x) = f(x) + g(x) = x² - x - 3