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Ali has a 64 gram bar of chocolate. on day 1 he eats half of his chocolate. on day 2 he eats half of what is left. he does the same each day.
a. when will he have only 1 gram left?
b. how much would a bar of chocolate need to weigh to last All 14 days?​

Respuesta :

Answer:

A: Day 6

B: 8196 grams (He will become obese for sure)

Step-by-step explanation:

Part A:

As you can infer from the problem, Ali halves his bar everyday, regardless of how the bar is.

Day 1= 32 grams left

Day 2= 16 grams left

Day 3= 8 grams left

Dat 4= 4 grams left

Day 5= 2 grams left

Day 6=1 gram left

He will have one gram left on Day 6

Part B:

This part is basically vice versa. Instead on halving, we need to be doubling. I will do Part a in reverse until Day 14 comes

Day 1= 1

Day 2= 2

Day 3= 4

Day 4= 8

Day 5= 16

Day 6= 32

Day 7 = 64

Day 8= 128

Day 9= 256

Day 10= 512

Day 11= 1024

Day 12= 2048

Day 13= 4096

Day 14= 8192

He will need 8192 grams of chocolate!!!

The number of days when he has only 1 gram left will be 6. And the chocolate needs to weigh to last All 14 days will be 1/256 grams.

What is an exponent?

Let a be the initial value and x be the power of the exponent function and b be the increasing factor.

The exponent is given as

y = a(b)ˣ

Ali has a 64 grams bar of chocolate.

On day 1 he eats half of his chocolate.

And on day 2 he eats half of what is left.

He does the same each day.

Then the value of a is 64 grams and b is 1/2.

y = 64 · (1/2)ⁿ

Where n is the number of days.

The number of days when he has only 1 gram left will be

1 = 64 · (1/2)ⁿ

1/64 = (1/2)ⁿ

(1/2)⁶ = (1/2)ⁿ

n = 6

The number of days when he has only 1 gram left will be 6.

The chocolate needs to weigh to last All 14 days will be

y = 64 · (1/2)¹⁴

y = 64 · (1/16384)

y = 1/256 grams

The chocolate needs to weigh to last All 14 days will be 1/256 grams.

More about the exponent link is given below.

https://brainly.com/question/5497425

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