Respuesta :

gmany

Step-by-step explanation:

The point-slope of an equation of a line:

[tex]y-y_1=m(x-x_1)[/tex]

m - slope

We have

[tex]m=1\\\\\left(\dfrac{3}{2},\ -\dfrac{1}{2}\right)\to x_1=\dfrac{3}{2},\ y_1=-\dfrac{1}{2}[/tex]

Substitute:

[tex]y-\left(-\dfrac{1}{2}\right)=1\left(x-\dfrac{3}{2}\right)[/tex]

[tex]y+\dfrac{1}{2}=1\left(x-\dfrac{3}{2}\right)[/tex] → the point-slope form

Convert to the slope-intercept form:

[tex]y+\dfrac{1}{2}=x-\dfrac{3}{2}[/tex]         subtract 1/2 from both sides

[tex]y=x-\dfrac{4}{2}[/tex]

[tex]y=x-2[/tex] → the slope-intercept form

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