Step-by-step explanation:
The point-slope of an equation of a line:
[tex]y-y_1=m(x-x_1)[/tex]
m - slope
We have
[tex]m=1\\\\\left(\dfrac{3}{2},\ -\dfrac{1}{2}\right)\to x_1=\dfrac{3}{2},\ y_1=-\dfrac{1}{2}[/tex]
Substitute:
[tex]y-\left(-\dfrac{1}{2}\right)=1\left(x-\dfrac{3}{2}\right)[/tex]
[tex]y+\dfrac{1}{2}=1\left(x-\dfrac{3}{2}\right)[/tex] → the point-slope form
Convert to the slope-intercept form:
[tex]y+\dfrac{1}{2}=x-\dfrac{3}{2}[/tex] subtract 1/2 from both sides
[tex]y=x-\dfrac{4}{2}[/tex]
[tex]y=x-2[/tex] → the slope-intercept form