The tangent half angle formula, one of several, is
[tex]\tan \dfrac a 2 = \dfrac{1 - \cos a}{\sin a}[/tex]
We have θ is opposite 4 in the 3/4/5 right triangle so
[tex]\cos \theta = \dfrac{3}{5}[/tex]
[tex]\sin \theta = \dfrac{4}{5}[/tex]
[tex]\tan \dfrac{\theta}{2} = \dfrac{1 - 3/5}{4/5} = \dfrac{5-3}{4}=\dfrac{1}{2}[/tex]
Answer: 1/2
This is actually pretty deep. It says half the big acute angle in the 3/4/5 triangle is the small diagonal angle of the 1x2 rectangle. Similarly, the small acute angle in 3/4/5 triangle is twice the small diagonal angle of the 1x3 rectangle.