Answer:
These kind of problem can be modeled by using the following equation
y = Po*e^(k*(t-to))
Where
Po = initial population
to = year of the initial population
y = Number of students at current year
k = constant rate of change
t = time in years
In 2012
695 = Po*e^(k*(2012 - 2012))
Po = 695
In 2016
825 = 695.e^(k*(2016-2012))
825/695 = e^(k*(4))
ln(825/695) = 4*k
k = ln(825/695) / 4
k = ln(825/695) / 4
k = 0.04287
in 2018
y = 695*e^(0.04287*(2018-2012))
y = 695*e^(0.04287*(6))
y = 695*e^(0.257)
y = 695*1.293
y = 898.85
approximately
899 students