Rolle's Theorem states that:
If f is a continuous function in [a,b] and is differentiable in (a,b)
such that f(a)=f(b)
Then there exist a constant c in between a and b i.e. c∈[a,b]
such that: f'(c)=0
Here we have the function f(x) as:
[tex]f(x)=4x^2-8x+3[/tex] where x∈[-1,3]
Also,
f(-1)=15
(Since,
[tex]f(-1)=4\times (-1)^2-8\times (-1)+3\\\\f(-1)=4+8+3\\\\f(-1)=15[/tex] )
and f(3)=15
( Since,
[tex]f(3)=4\times 3^2-8\times 3+3\\\\f(3)=36-24+3\\\\i.e.\\\\f(3)=15[/tex] )
Hence, there will exist a c∈[-1,3] such that f'(c)=0
[tex]f'(x)=8x-8\\\\i.e.\\\\f'(x)=0\\\\imply\\\\8x-8=0\\\\i.e.\\\\x-1=0\\\\i.e.\\\\x=1[/tex]
Hence, the c that satisfy the conclusion is: c=1