Answer:
The angle required in the water is 32°.
Explanation:
Given that,
Grade in the north = 12.5 %
Grade in the east = 20 %
We need to calculate the angle
We know that,
[tex]tan\theta=\dfrac{North}{East}[/tex]
[tex]tan\theta=\dfrac{12.5}{20}[/tex]
[tex]tan\theta=0.625[/tex]
[tex]\theta=tan^{-1}0.625[/tex]
[tex]\theta=32^{\circ}[/tex]
Hence, The angle required in the water is 32°.