Answer:
902 ft
Explanation:
First convert mi/h to ft/s.
53.0 mi/h × (5280 ft / mi) × (1 h / 3600 s) = 77.7 ft/s
Sum of the forces on the car in the y direction:
∑F = ma
N - W = 0
N = mg
Sum of the forces on the car in the x direction:
∑F = ma
-F = ma
-Nμ = ma
Substituting;
-mgμ = ma
-gμ = a
Acceleration is constant, so:
v² = v₀² + 2a(x - x₀)
(0 ft/s)² = (77.7 ft/s)² + 2(-32.2 ft/s² × 0.104)(x - 0)
x = 902 ft
The minimum stopping distance is 902 ft.
