Please help picture is there

Answer:
B
Step-by-step explanation:
Using the rule of radicals/ exponents
[tex]\sqrt{a}[/tex] × [tex]\sqrt{b}[/tex] ⇔ [tex]\sqrt{ab}[/tex]
[tex]a^{\frac{m}{n} }[/tex] ⇔ [tex]\sqrt[n]{a^{m} }[/tex]
Given
[tex]\sqrt[3]{x^5 y}[/tex]
= [tex]\sqrt[3]{x^5}[/tex] × [tex]\sqrt[3]{y}[/tex]
= [tex]x^{\frac{5}{3} }[/tex] [tex]y^{\frac{1}{3} }[/tex] → B