Question

There are 8 movies that you would like to see currently showing in theatres. In how many different ways can you choose a movie to see this Saturday and one to see this Sunday?

Answer 1

Answer:

56

Step-by-step explanation:

Assumption: You don't watch the same movie twice

I will explain in 2 ways

METHOD 1: Multiplication Rule

On Saturday, you have 8 choices. On Sunday, you have 7 choices because u have already watched 1 movie on Saturday

8×7 = 56

METHOD 2: Permutation

Since 'order' is important, i.e. watching movie A on Saturday & B on Sunday is different from watching B on Saturday & A on Sunday, so it's

8P2 = 56

Answer 2

Using the permutation formula, it is found that you can choose a movie to see this Saturday and one to see this Sunday in 56 ways.

The order in which the movies are chosen is important, as they are respective to different days, hence the permutation formula is used to solve this question.

What is the permutation formula?

The number of possible permutations of x elements from a set of n elements is given by:

$P_{(n,x)} = \frac{n!}{(n-x)!}$

In this problem, 2 movies will be chosen from a set of 8, hence:

$P_{(8,2)} = \frac{8!}{6!} = 8 \times 7 = 56$

Hence, you can choose a movie to see this Saturday and one to see this Sunday in 56 ways.

More can be learned about the permutation formula at https://brainly.com/question/25925367