Question

Factor this polynomial completely.
12x^2+ x-6

Answer 1

Answer:

(3 x - 2) (4 x + 3)

Step-by-step explanation:

Factor the following:

12 x^2 + x - 6

Factor the quadratic 12 x^2 + x - 6.

The coefficient of x^2 is 12 and the constant term is -6.

The product of 12 and -6 is -72. The factors of -72 which sum to 1 are -8 and 9.

So 12 x^2 + x - 6 = 12 x^2 + 9 x - 8 x - 6 = 3 (3 x - 2) + 4 x (3 x - 2):

3 (3 x - 2) + 4 x (3 x - 2)

Factor 3 x - 2 from 3 (3 x - 2) + 4 x (3 x - 2):

Answer:  (3 x - 2) (4 x + 3)

Answer 2

The answer is (3 x - 2) (4 x + 3).

Polynomials

Polynomial exists an algebraic expression with terms divided utilizing the operators "+" and "-" in which the exponents of variables exist always nonnegative integers.

Factor the following:

$12x^{2}+x-6$

Factor the quadratic

$12x^{2} +x-6$

The coefficient  $x^{2}$ is 12 and the constant term is -6.

The product of 12 and -6 is -72.

The factors of -72 which sum to 1 exist at -8 and 9.

So

$12 x^{2} +x-6=12 x^{2} +9 x-8 x-6$

$=3(3 x-2)+4 x(3 x-2)$

$3(3 x-2)+4 x(3 x-2)$

Factor 3 x - 2 from 3 (3 x - 2) + 4 x (3 x - 2)

Hence, The answer is (3 x - 2) (4 x + 3).

To learn more about Polynomials refer to:

https://brainly.com/question/13769924

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