Question

A rubber ball contains 5.70*10⁻¹ dm³ of gas at a pressure of 1.05 atm. What volume will the gas occupy at 7.47 atm?

Answer 1

Assuming ideal gas behavior:

P1V1 = P2V2

V2 = P1V1/P2 = 1.05 atm * 0.570 liters / 7.47 atm = 0.080 liters