Answer:
45-2(h-1)<32
Step-by-step explanation:
This is a problem related to arithmetic progression. The formula we use is that of for nth term
[tex]a_{n}=a+(n-1)d[/tex]
Here
[tex]a=45 , d=-2 ,n=h , a_{n}=a_{h}[/tex]
[tex]a_{h}=45+(h-1)(-2)\\a_{h}=45-2(h-1)\\[/tex]
Now we have to analyse a situation when our temperature comes below 32
or
[tex]a_{h}<32[tex]
[tex]45-2(h-1)<32\\45-2h+2<32\\45-2h<32-2\\45-2h<30\\[/tex]
This is our inequality
Solving this
[tex]45-2h<30\\-2h<30-45\\-2h<-15\\h>7.5\\[/tex]
Hence in 8th hours the temperature will be below 32F