Question

using the quadratic formula to solve 5x=6x squared -3, what are the values of x?

Answer 1

Answer: 5+sqrt(97)/12, 5-sqrt(97)/12 or we write it as [5+/-sqrt(97)]/(12)

5x=6x^2-3

6x^2-5x-3=0

x=-b+/-sqrt(b^2-4ac)/2a

x=-(-5)+/-sqrt((-5^2-4(6)(-3))/2(6)

x= 5+/-sqrt(97)/12

And decimal form is;

x=1.237, -0.4041

If anyone has any questions please feel free to ask and I’ll reply ASAP. Thanks